Patriots lose Flowers, Brown to free agency

FOXBORO — The Patriots will once again look to restock with new players in key positions after losing familiar faces to free agency.

According to multiple reports, offensive tackle Trent Brown has agreed to a deal with the Oakland Raiders and defensive end Trey Flowers has agreed to a deal with the Detroit Lions.

Brown's deal, said to be worth four years and $66 million, and Flowers deal, said to be for five years, was first reported by ESPN's Adam Schefter.

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Flowers spent four years with the Patriots after being selected in the fourth round of the 2015 NFL Draft. He played in three Super Bowls, winning two.

Field Yates, also of ESPN, reported  that Flowers' expected deal with Detroit is worth roughly $16-$17 million per season.

The defensive end is coming off of a four-year deal in New England, where he signed for roughly $2.8 million back in 2015 after the Patriots selected the Arkansas product with the 101st overall pick.

The edge rusher played four seasons for New England, leading the team with 7.5 sacks and three forced fumbles in the 2018-2019 season.

After appearing in just one game in his first season back in 2015, Flowers played in 45 contests across the last three years, 37 of which he started. The defensive end will turn 26 on August 16.

New England will receive a third-round compensatory pick in the 2020 NFL Draft in exchange for the loss of Flowers, according to Schefter.

>>>MORE: Dolphins reportedly release former Patriots WR Danny Amendola

Brown was acquired in a trade with the San Francisco 49ers in April and played 16 regular season and three postseason games at left tackle.

Also today, former Patriots wide receiver Danny Amendola, who spent the 2018 season with Dolphins, agreed to a one-year deal with the Lions.

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